60x^2+68x-16=0

Solution for 60x^2+68x-16=0 equation:

60x^2+68x-16=0

a = 60; b = 68; c = -16;
Δ = b2-4ac
Δ = 682-4·60·(-16)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-92}{2*60}=\frac{-160}{120}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+92}{2*60}=\frac{24}{120}
=1/5
$